1 Ml of Ricotta to Pounds Conversion

Question:
How many pounds of ricotta in 1 milliliter? How much is 1 ml of ricotta in pounds?

The answer is:
1 milliliter of ricotta is equivalent to 0.00233 pounds(*)

Volume to 'Weight' Converter

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Results:

1 milliliter of ricotta equals 0.00233 pounds. (*)
(*) To be more precise, 1 milliliter of ricotta is equal to 0.0023303 pounds. All figures are approximate.

Milliliters of ricotta to pounds Chart

Milliliters of ricotta to pounds
0.1 milliliters of ricotta = 0.000233 pounds
1/5 milliliters of ricotta = 0.000466 pounds
0.3 milliliters of ricotta = 0.000699 pounds
0.4 milliliters of ricotta = 0.000932 pounds
1/2 milliliters of ricotta = 0.00117 pounds
0.6 milliliters of ricotta = 0.0014 pounds
0.7 milliliters of ricotta = 0.00163 pounds
0.8 milliliters of ricotta = 0.00186 pounds
0.9 milliliters of ricotta = 0.0021 pounds
1 milliliter of ricotta = 0.00233 pounds
Milliliters of ricotta to pounds
1 milliliter of ricotta = 0.00233 pounds
1.1 milliliters of ricotta = 0.00256 pounds
1/5 milliliters of ricotta = 0.0028 pounds
1.3 milliliters of ricotta = 0.00303 pounds
1.4 milliliters of ricotta = 0.00326 pounds
1/2 milliliters of ricotta = 0.0035 pounds
1.6 milliliters of ricotta = 0.00373 pounds
1.7 milliliters of ricotta = 0.00396 pounds
1.8 milliliters of ricotta = 0.00419 pounds
1.9 milliliters of ricotta = 0.00443 pounds

Note: some values may be rounded.

FAQs on ricotta weight to volume conversion

1 milliliter of ricotta equals how many pounds?

1 milliliter of ricotta is equivalent 0.00233 pounds.

How much is 0.00233 pounds of ricotta in milliliters?

0.00233 pounds of ricotta equals 1 milliliter.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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