1 1/2 Cups of Cacao Powder to Grams Conversion
Question:
How many grams of cacao powder in 1 1/2 US cups? How much are 1 1/2 cups of cacao powder in grams?
The answer is:
1 1/2 US cups of cacao powder is equivalent to 150 grams(*)
Volume to 'Weight' Converter
US cups of cacao powder to grams Chart
US cups of cacao powder to grams | ||
---|---|---|
0.6 US cups of cacao powder | = | 60 grams |
0.7 US cups of cacao powder | = | 70.1 grams |
0.8 US cups of cacao powder | = | 80.1 grams |
0.9 US cups of cacao powder | = | 90.1 grams |
1 US cup of cacao powder | = | 100 grams |
1.1 US cups of cacao powder | = | 110 grams |
1 1/5 US cups of cacao powder | = | 120 grams |
1.3 US cups of cacao powder | = | 130 grams |
1.4 US cups of cacao powder | = | 140 grams |
1 1/2 US cups of cacao powder | = | 150 grams |
US cups of cacao powder to grams | ||
---|---|---|
1 1/2 US cups of cacao powder | = | 150 grams |
1.6 US cups of cacao powder | = | 160 grams |
1.7 US cups of cacao powder | = | 170 grams |
1.8 US cups of cacao powder | = | 180 grams |
1.9 US cups of cacao powder | = | 190 grams |
2 US cups of cacao powder | = | 200 grams |
2.1 US cups of cacao powder | = | 210 grams |
2 1/5 US cups of cacao powder | = | 220 grams |
2.3 US cups of cacao powder | = | 230 grams |
2.4 US cups of cacao powder | = | 240 grams |
Note: some values may be rounded.
FAQs on cacao powder weight to volume conversion
1 1/2 US cups of cacao powder equals how many grams?
1 1/2 US cups of cacao powder is equivalent 150 grams.
How much is 150 grams of cacao powder in US cups?
150 grams of cacao powder equals 1 1/2 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.