10 Cups of Mint Leaves to Pounds Conversion

Question:
How many pounds of mint leaves in 10 US cups? How much are 10 cups of mint leaves in pounds?

The answer is:
10 US cups of mint leaves is equivalent to 0.662 ( ~ 3/4) pounds(*)

Volume to 'Weight' Converter

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Results:

10 US cups of mint leaves equals 0.662 ( ~ 3/4) pounds. (*)
(*) To be more precise, 10 US cups of mint leaves is equal to 0.66242 pounds. All figures are approximate.

US cups of mint leaves to pounds Chart

US cups of mint leaves to pounds
1 US cup of mint leaves = 0.0662 pounds
2 US cups of mint leaves = 0.132 pounds
3 US cups of mint leaves = 0.199 pounds
4 US cups of mint leaves = 0.265 pounds
5 US cups of mint leaves = 0.331 pounds
6 US cups of mint leaves = 0.397 pounds
7 US cups of mint leaves = 0.464 pounds
8 US cups of mint leaves = 0.53 pounds
9 US cups of mint leaves = 0.596 pounds
10 US cups of mint leaves = 0.662 pounds
US cups of mint leaves to pounds
10 US cups of mint leaves = 0.662 pounds
11 US cups of mint leaves = 0.729 pounds
12 US cups of mint leaves = 0.795 pounds
13 US cups of mint leaves = 0.861 pounds
14 US cups of mint leaves = 0.927 pounds
15 US cups of mint leaves = 0.994 pounds
16 US cups of mint leaves = 1.06 pounds
17 US cups of mint leaves = 1.13 pounds
18 US cups of mint leaves = 1.19 pounds
19 US cups of mint leaves = 1.26 pounds

Note: some values may be rounded.

FAQs on mint leaves weight to volume conversion

10 US cups of mint leaves equals how many pounds?

10 US cups of mint leaves is equivalent 0.662 ( ~ 3/4) pounds.

How much is 0.662 pounds of mint leaves in US cups?

0.662 pounds of mint leaves equals 10 ( ~ 10) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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