16 Cups of Margarine to Pounds Conversion

Question:
How many pounds of margarine in 16 US cups? How much are 16 cups of margarine in pounds?

The answer is:
16 US cups of margarine is equivalent to 8.82 ( ~ 8 3/4) pounds(*)

Volume to 'Weight' Converter

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Results:

16 US cups of margarine equals 8.82 ( ~ 8 3/4) pounds. (*)
(*) To be more precise, 16 US cups of margarine is equal to 8.8211 pounds. All figures are approximate.

US cups of margarine to pounds Chart

US cups of margarine to pounds
7 US cups of margarine = 3.86 pounds
8 US cups of margarine = 4.41 pounds
9 US cups of margarine = 4.96 pounds
10 US cups of margarine = 5.51 pounds
11 US cups of margarine = 6.06 pounds
12 US cups of margarine = 6.62 pounds
13 US cups of margarine = 7.17 pounds
14 US cups of margarine = 7.72 pounds
15 US cups of margarine = 8.27 pounds
16 US cups of margarine = 8.82 pounds
US cups of margarine to pounds
16 US cups of margarine = 8.82 pounds
17 US cups of margarine = 9.37 pounds
18 US cups of margarine = 9.92 pounds
19 US cups of margarine = 10.5 pounds
20 US cups of margarine = 11 pounds
21 US cups of margarine = 11.6 pounds
22 US cups of margarine = 12.1 pounds
23 US cups of margarine = 12.7 pounds
24 US cups of margarine = 13.2 pounds
25 US cups of margarine = 13.8 pounds

Note: some values may be rounded.

FAQs on margarine weight to volume conversion

16 US cups of margarine equals how many pounds?

16 US cups of margarine is equivalent 8.82 ( ~ 8 3/4) pounds.

How much is 8.82 pounds of margarine in US cups?

8.82 pounds of margarine equals 16 ( ~ 16) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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