2/3 Cups of Ice Cream to Pounds Conversion
Question:
How many pounds of ice cream in 2/3 US cups? How much is 2/3 cups of ice cream in pounds?
The answer is:
2/3 US cups of ice cream is equivalent to 0.22 ( ~
Volume to 'Weight' Converter
US cups of ice cream to pounds Chart
US cups of ice cream to pounds | ||
---|---|---|
0.5767 US cups of ice cream | = | 0.191 pounds |
0.5867 US cups of ice cream | = | 0.194 pounds |
0.5967 US cups of ice cream | = | 0.197 pounds |
0.6067 US cups of ice cream | = | 0.201 pounds |
0.6167 US cups of ice cream | = | 0.204 pounds |
0.6267 US cups of ice cream | = | 0.207 pounds |
0.6367 US cups of ice cream | = | 0.211 pounds |
0.6467 US cups of ice cream | = | 0.214 pounds |
0.6567 US cups of ice cream | = | 0.217 pounds |
0.667 US cups of ice cream | = | 0.22 pounds |
US cups of ice cream to pounds | ||
---|---|---|
0.667 US cups of ice cream | = | 0.22 pounds |
0.6767 US cups of ice cream | = | 0.224 pounds |
0.6867 US cups of ice cream | = | 0.227 pounds |
0.6967 US cups of ice cream | = | 0.23 pounds |
0.7067 US cups of ice cream | = | 0.234 pounds |
0.7167 US cups of ice cream | = | 0.237 pounds |
0.7267 US cups of ice cream | = | 0.24 pounds |
0.7367 US cups of ice cream | = | 0.244 pounds |
0.7467 US cups of ice cream | = | 0.247 pounds |
0.7567 US cups of ice cream | = | 0.25 pounds |
Note: some values may be rounded.
FAQs on ice cream weight to volume conversion
2/3 US cups of ice cream equals how many pounds?
2/3 US cups of ice cream is equivalent 0.22 ( ~
How much is 0.22 pounds of ice cream in US cups?
0.22 pounds of ice cream equals 2/3 ( ~
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.