35 Ml of Raisins to Pounds Conversion
Question:
How many pounds of raisins in 35 milliliters? How much are 35 ml of raisins in pounds?
The answer is:
35 milliliters of raisins is equivalent to 0.0519 pounds(*)
Volume to 'Weight' Converter
Milliliters of raisins to pounds Chart
Milliliters of raisins to pounds | ||
---|---|---|
26 milliliters of raisins | = | 0.0385 pounds |
27 milliliters of raisins | = | 0.04 pounds |
28 milliliters of raisins | = | 0.0415 pounds |
29 milliliters of raisins | = | 0.043 pounds |
30 milliliters of raisins | = | 0.0444 pounds |
31 milliliters of raisins | = | 0.0459 pounds |
32 milliliters of raisins | = | 0.0474 pounds |
33 milliliters of raisins | = | 0.0489 pounds |
34 milliliters of raisins | = | 0.0504 pounds |
35 milliliters of raisins | = | 0.0519 pounds |
Milliliters of raisins to pounds | ||
---|---|---|
35 milliliters of raisins | = | 0.0519 pounds |
36 milliliters of raisins | = | 0.0533 pounds |
37 milliliters of raisins | = | 0.0548 pounds |
38 milliliters of raisins | = | 0.0563 pounds |
39 milliliters of raisins | = | 0.0578 pounds |
40 milliliters of raisins | = | 0.0593 pounds |
41 milliliters of raisins | = | 0.0607 pounds |
42 milliliters of raisins | = | 0.0622 pounds |
43 milliliters of raisins | = | 0.0637 pounds |
44 milliliters of raisins | = | 0.0652 pounds |
Note: some values may be rounded.
FAQs on raisins weight to volume conversion
35 milliliters of raisins equals how many pounds?
35 milliliters of raisins is equivalent 0.0519 pounds.
How much is 0.0519 pounds of raisins in milliliters?
0.0519 pounds of raisins equals 35 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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