5 Ml of Potato to Kg Conversion

Question:
How many kilograms of potato in 5 milliliters? How much are 5 ml of potato in kg?

The answer is:
5 milliliters of potato is equivalent to 0.00295 kilogram(*)

Volume to 'Weight' Converter

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Results:

5 milliliters of potato equals 0.00295 kilogram. (*)
(*) To be more precise, 5 milliliters of potato is equal to 0.00295 kilogram. All figures are approximate.

Milliliters of potato to kilograms Chart

Milliliters of potato to kilograms
4.1 milliliters of potato = 0.00242 kilogram
1/5 milliliters of potato = 0.00248 kilogram
4.3 milliliters of potato = 0.00254 kilogram
4.4 milliliters of potato = 0.0026 kilogram
1/2 milliliters of potato = 0.00266 kilogram
4.6 milliliters of potato = 0.00271 kilogram
4.7 milliliters of potato = 0.00277 kilogram
4.8 milliliters of potato = 0.00283 kilogram
4.9 milliliters of potato = 0.00289 kilogram
5 milliliters of potato = 0.00295 kilogram
Milliliters of potato to kilograms
5 milliliters of potato = 0.00295 kilogram
5.1 milliliters of potato = 0.00301 kilogram
1/5 milliliters of potato = 0.00307 kilogram
5.3 milliliters of potato = 0.00313 kilogram
5.4 milliliters of potato = 0.00319 kilogram
1/2 milliliters of potato = 0.00325 kilogram
5.6 milliliters of potato = 0.0033 kilogram
5.7 milliliters of potato = 0.00336 kilogram
5.8 milliliters of potato = 0.00342 kilogram
5.9 milliliters of potato = 0.00348 kilogram

Note: some values may be rounded.

FAQs on potato weight to volume conversion

5 milliliters of potato equals how many kilograms?

5 milliliters of potato is equivalent 0.00295 kilogram.

How much is 0.00295 kilogram of potato in milliliters?

0.00295 kilogram of potato equals 5 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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