5 Ml of Rice to Kg Conversion
Question:
How many kilograms of rice in 5 milliliters? How much are 5 ml of rice in kg?
The answer is:
5 milliliters of rice is equivalent to 0.00423 kilogram(*)
Volume to 'Weight' Converter
Milliliters of rice to kilograms Chart
Milliliters of rice to kilograms | ||
---|---|---|
4.1 milliliters of rice | = | 0.00346 kilogram |
4 1/5 milliliters of rice | = | 0.00355 kilogram |
4.3 milliliters of rice | = | 0.00363 kilogram |
4.4 milliliters of rice | = | 0.00372 kilogram |
4 1/2 milliliters of rice | = | 0.0038 kilogram |
4.6 milliliters of rice | = | 0.00389 kilogram |
4.7 milliliters of rice | = | 0.00397 kilogram |
4.8 milliliters of rice | = | 0.00406 kilogram |
4.9 milliliters of rice | = | 0.00414 kilogram |
5 milliliters of rice | = | 0.00423 kilogram |
Milliliters of rice to kilograms | ||
---|---|---|
5 milliliters of rice | = | 0.00423 kilogram |
5.1 milliliters of rice | = | 0.00431 kilogram |
5 1/5 milliliters of rice | = | 0.00439 kilogram |
5.3 milliliters of rice | = | 0.00448 kilogram |
5.4 milliliters of rice | = | 0.00456 kilogram |
5 1/2 milliliters of rice | = | 0.00465 kilogram |
5.6 milliliters of rice | = | 0.00473 kilogram |
5.7 milliliters of rice | = | 0.00482 kilogram |
5.8 milliliters of rice | = | 0.0049 kilogram |
5.9 milliliters of rice | = | 0.00499 kilogram |
Note: some values may be rounded.
FAQs on rice weight to volume conversion
5 milliliters of rice equals how many kilograms?
5 milliliters of rice is equivalent 0.00423 kilogram.
How much is 0.00423 kilogram of rice in milliliters?
0.00423 kilogram of rice equals 5 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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