A Fifth Cup of Dry Lentils to Pounds Conversion

Question:
How many pounds of dry lentils in A Fifth US cup? How much is A Fifth cup of dry lentils in pounds?

The answer is:
a fifth US cup of dry lentils is equivalent to 0.0881 pound(*)

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Results:

a fifth US cup of dry lentils equals 0.0881 pound. (*)
(*) To be more precise, a fifth US cup of dry lentils is equal to 0.088148 pound. All figures are approximate.

US cups of dry lentils to pounds Chart

US cups of dry lentils to pounds
0.11 US cup of dry lentils = 0.0485 pound
0.12 US cup of dry lentils = 0.0529 pound
0.13 US cup of dry lentils = 0.0573 pound
0.14 US cup of dry lentils = 0.0617 pound
0.15 US cup of dry lentils = 0.0661 pound
0.16 US cup of dry lentils = 0.0705 pound
0.17 US cup of dry lentils = 0.0749 pound
0.18 US cup of dry lentils = 0.0793 pound
0.19 US cup of dry lentils = 0.0837 pound
1/5 US cup of dry lentils = 0.0881 pound
US cups of dry lentils to pounds
1/5 US cup of dry lentils = 0.0881 pound
0.21 US cup of dry lentils = 0.0926 pound
0.22 US cup of dry lentils = 0.097 pound
0.23 US cup of dry lentils = 0.101 pound
0.24 US cup of dry lentils = 0.106 pound
1/4 US cup of dry lentils = 0.11 pound
0.26 US cup of dry lentils = 0.115 pound
0.27 US cup of dry lentils = 0.119 pound
0.28 US cup of dry lentils = 0.123 pound
0.29 US cup of dry lentils = 0.128 pound

Note: some values may be rounded.

FAQs on dry lentils weight to volume conversion

A fifth US cup of dry lentils equals how many pounds?

A fifth US cup of dry lentils is equivalent 0.0881 pound.

How much is 0.0881 pound of dry lentils in US cups?

0.0881 pound of dry lentils equals a fifth ( ~ 1/4) US cup.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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