1 Gram of Icing Sugar to Cups Conversion
Questions: How many US cups of icing sugar in 1 gram? How much is 1 gram of icing sugar in cups?
The answer is: 1 gram of icing sugar is equivalent to 0.00801 US cups(*)
'Weight' to Volume Converter
Grams of icing sugar to US cups Chart
Grams of icing sugar to US cups | ||
---|---|---|
0.1 grams of icing sugar | = | 0.000801 US cups |
1/5 grams of icing sugar | = | 0.0016 US cups |
0.3 grams of icing sugar | = | 0.0024 US cups |
0.4 grams of icing sugar | = | 0.0032 US cups |
1/2 grams of icing sugar | = | 0.004 US cups |
0.6 grams of icing sugar | = | 0.0048 US cups |
0.7 grams of icing sugar | = | 0.0056 US cups |
0.8 grams of icing sugar | = | 0.0064 US cups |
0.9 grams of icing sugar | = | 0.0072 US cups |
1 gram of icing sugar | = | 0.00801 US cups |
Grams of icing sugar to US cups | ||
---|---|---|
1 gram of icing sugar | = | 0.00801 US cups |
1.1 grams of icing sugar | = | 0.00881 US cups |
1 1/5 grams of icing sugar | = | 0.00961 US cups |
1.3 grams of icing sugar | = | 0.0104 US cups |
1.4 grams of icing sugar | = | 0.0112 US cups |
1 1/2 grams of icing sugar | = | 0.012 US cups |
1.6 grams of icing sugar | = | 0.0128 US cups |
1.7 grams of icing sugar | = | 0.0136 US cups |
1.8 grams of icing sugar | = | 0.0144 US cups |
1.9 grams of icing sugar | = | 0.0152 US cups |
Note: some values may be rounded.
FAQs on icing sugar volume to weight conversion
1 gram of icing sugar equals how many US cups?
1 gram of icing sugar is equivalent 0.00801 US cups.
How much is 0.00801 US cups of icing sugar in grams?
0.00801 US cups of icing sugar equals 1 gram.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.