20 Grams of Castor Oil to Cups Conversion

Questions: How many US cups of castor oil in 20 grams? How much are 20 grams of castor oil in cups?

The answer is: 20 grams of castor oil is equivalent to 0.088 US cups^(*)

'Weight' to Volume Converter

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Results
20 grams of castor oil equals 0.088 US cups.
(*) To be more precise, 20 grams of castor oil is equal to 0.087966 US cups. All figures are approximate.
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Grams of castor oil to US cups Chart

Grams of castor oil to US cups
11 grams of castor oil	=	0.0484 US cups
12 grams of castor oil	=	0.0528 US cups
13 grams of castor oil	=	0.0572 US cups
14 grams of castor oil	=	0.0616 US cups
15 grams of castor oil	=	0.066 US cups
16 grams of castor oil	=	0.0704 US cups
17 grams of castor oil	=	0.0748 US cups
18 grams of castor oil	=	0.0792 US cups
19 grams of castor oil	=	0.0836 US cups
20 grams of castor oil	=	0.088 US cups

Grams of castor oil to US cups
20 grams of castor oil	=	0.088 US cups
21 grams of castor oil	=	0.0924 US cups
22 grams of castor oil	=	0.0968 US cups
23 grams of castor oil	=	0.101 US cups
24 grams of castor oil	=	0.106 US cups
25 grams of castor oil	=	0.11 US cups
26 grams of castor oil	=	0.114 US cups
27 grams of castor oil	=	0.119 US cups
28 grams of castor oil	=	0.123 US cups
29 grams of castor oil	=	0.128 US cups

Note: some values may be rounded.

FAQs on castor oil volume to weight conversion

20 grams of castor oil equals how many US cups?

20 grams of castor oil is equivalent 0.088 US cups.

How much is 0.088 US cups of castor oil in grams?

0.088 US cups of castor oil equals 20 grams.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.