35 Grams of Cocoa Powder to Ml Conversion

Questions: How many milliliters of cocoa powder in 35 grams? How much are 35 grams of cocoa powder in ml?

The answer is: 35 grams of cocoa powder is equivalent to 69 milliliters(*)

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Results

35 grams of cocoa powder equals 69 milliliters.
(*) To be more precise, 35 grams of cocoa powder is equal to 69.034 milliliters. All figures are approximate.

Grams of cocoa powder to milliliters Chart

Grams of cocoa powder to milliliters
26 grams of cocoa powder = 51.3 milliliters
27 grams of cocoa powder = 53.3 milliliters
28 grams of cocoa powder = 55.2 milliliters
29 grams of cocoa powder = 57.2 milliliters
30 grams of cocoa powder = 59.2 milliliters
31 grams of cocoa powder = 61.1 milliliters
32 grams of cocoa powder = 63.1 milliliters
33 grams of cocoa powder = 65.1 milliliters
34 grams of cocoa powder = 67.1 milliliters
35 grams of cocoa powder = 69 milliliters
Grams of cocoa powder to milliliters
35 grams of cocoa powder = 69 milliliters
36 grams of cocoa powder = 71 milliliters
37 grams of cocoa powder = 73 milliliters
38 grams of cocoa powder = 75 milliliters
39 grams of cocoa powder = 76.9 milliliters
40 grams of cocoa powder = 78.9 milliliters
41 grams of cocoa powder = 80.9 milliliters
42 grams of cocoa powder = 82.8 milliliters
43 grams of cocoa powder = 84.8 milliliters
44 grams of cocoa powder = 86.8 milliliters

Note: some values may be rounded.

FAQs on cocoa powder volume to weight conversion

35 grams of cocoa powder equals how many milliliters?

35 grams of cocoa powder is equivalent 69 milliliters.

How much is 69 milliliters of cocoa powder in grams?

69 milliliters of cocoa powder equals 35 grams.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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