50 Ml of Raisins to Pounds Conversion
Question:
How many pounds of raisins in 50 milliliters? How much are 50 ml of raisins in pounds?
The answer is:
50 milliliters of raisins is equivalent to 0.0741 pounds(*)
Volume to 'Weight' Converter
Milliliters of raisins to pounds Chart
Milliliters of raisins to pounds | ||
---|---|---|
41 milliliters of raisins | = | 0.0607 pounds |
42 milliliters of raisins | = | 0.0622 pounds |
43 milliliters of raisins | = | 0.0637 pounds |
44 milliliters of raisins | = | 0.0652 pounds |
45 milliliters of raisins | = | 0.0667 pounds |
46 milliliters of raisins | = | 0.0681 pounds |
47 milliliters of raisins | = | 0.0696 pounds |
48 milliliters of raisins | = | 0.0711 pounds |
49 milliliters of raisins | = | 0.0726 pounds |
50 milliliters of raisins | = | 0.0741 pounds |
Milliliters of raisins to pounds | ||
---|---|---|
50 milliliters of raisins | = | 0.0741 pounds |
51 milliliters of raisins | = | 0.0756 pounds |
52 milliliters of raisins | = | 0.077 pounds |
53 milliliters of raisins | = | 0.0785 pounds |
54 milliliters of raisins | = | 0.08 pounds |
55 milliliters of raisins | = | 0.0815 pounds |
56 milliliters of raisins | = | 0.083 pounds |
57 milliliters of raisins | = | 0.0844 pounds |
58 milliliters of raisins | = | 0.0859 pounds |
59 milliliters of raisins | = | 0.0874 pounds |
Note: some values may be rounded.
FAQs on raisins weight to volume conversion
50 milliliters of raisins equals how many pounds?
50 milliliters of raisins is equivalent 0.0741 pounds.
How much is 0.0741 pounds of raisins in milliliters?
0.0741 pounds of raisins equals 50 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.