30 Grams of Chopped Onion to Cups Conversion
Questions: How many US cups of chopped onion in 30 grams? How much are 30 grams of chopped onion in cups?
The answer is: 30 grams of chopped onion is equivalent to 0.576 ( ~
'Weight' to Volume Converter
Grams of chopped onion to US cups Chart
Grams of chopped onion to US cups | ||
---|---|---|
21 grams of chopped onion | = | 0.403 US cup |
22 grams of chopped onion | = | 0.423 US cup |
23 grams of chopped onion | = | 0.442 US cup |
24 grams of chopped onion | = | 0.461 US cup |
25 grams of chopped onion | = | 0.48 US cup |
26 grams of chopped onion | = | 0.5 US cup |
27 grams of chopped onion | = | 0.519 US cup |
28 grams of chopped onion | = | 0.538 US cup |
29 grams of chopped onion | = | 0.557 US cup |
30 grams of chopped onion | = | 0.576 US cup |
Grams of chopped onion to US cups | ||
---|---|---|
30 grams of chopped onion | = | 0.576 US cup |
31 grams of chopped onion | = | 0.596 US cup |
32 grams of chopped onion | = | 0.615 US cup |
33 grams of chopped onion | = | 0.634 US cup |
34 grams of chopped onion | = | 0.653 US cup |
35 grams of chopped onion | = | 0.672 US cup |
36 grams of chopped onion | = | 0.692 US cup |
37 grams of chopped onion | = | 0.711 US cup |
38 grams of chopped onion | = | 0.73 US cup |
39 grams of chopped onion | = | 0.749 US cup |
Note: some values may be rounded.
FAQs on chopped onion volume to weight conversion
30 grams of chopped onion equals how many US cups?
30 grams of chopped onion is equivalent 0.576 ( ~
How much is 0.576 US cup of chopped onion in grams?
0.576 US cup of chopped onion equals 30 grams.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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